Feeding a Jig

According to Richard the interstitial relation is found in the following supposed form:

Feeding a jig with a pulp of mix of: 1.7 – 1.0 – 0.5 – 0.4 – 0. and 0.1 mm.; respectively, it was proven that the 0.4 mm. particles and less are better separated than the ones of 0.5 mm. on up to 1.7 mm.

The jig operates with 300 pulses per minute considering these factors the interstitial relation is determined:

• 1.7/0.4 = 4.25
• Where, d = D/4.25

For the calculus of speed of the grains, Monroe gives the formula:

• V = 26.32 D (d – 1)
• V = velocity in mm.
• D = diameter medium grain
• d = density.
• Richard gives 60V = 2cn.

It is necessary to increase the revolutions to 190 RPM.

The maximum speed of an eccentric with a minimum time of 0.2 seconds of dead point for each cycle gives us: 60/0.2 = 300 RPM.

With one time maximum of 0.5 seconds of dead point for each cycle gives us 60/0.5 = 120 RPM.

e) Schedule capacities
Primary jig of 42” (3.5 feet) with varied pelletmetry of -3mm. + 120 mesh.
Works: 17 tons/hour
Secondary jig of 42”, equals previous pelletmetry.
Works: 25 tons/hour
Tertiary jig of 42”, equals previous pelletmetry.
Works: 30 tons/hour