Battery Jigs

Units of primary jig. This consists on two stalls, and these carry out gravel classification in a semi stationary bed, with a percentage of 25 percent of solids and 75 percent in liquid. By effects of pulsation and suction that a membrane or diaphragm carries out by means of a piston that is started up by a motor (the same functioning principle for the secondary and tertiary jigs). The function of the primary jig is to separate the light material from the heavy material, through a process of sedimentation in a watery environment or pulp according to the specific weights or densities.

Units of secondary jigs. This consists of two types of stalls and carries out gravel classification in a semi stationary bed a percentage of 50 percent of solids and liquids respectively. It takes on heavier materials that were treated in primary jigs in the pre concentrated stage.

Units of tertiary jigs. The function and idea of the tertiary jigs are essentially the same than that of the primary and secondary jigs. These carry out gravel classification of in the final stages, the pulp at this stage consists of 75 percent solids and 25 percent of liquids.

Work method of the jigs. The cyclic operations of pulsation and suction enable the heavier particles to infiltrate through the interstitial spaces, including the heavier ones and eliminating those that are lighter weight. The interstitial relation can be found in the following way: feeding a jig with a mixture of pulp of 1.7 – 1.0 – 0.5 – 0.4 mm. respectively, it was seen that the particles of 0.4 mm. and less separated better than those of 0.5 mm. and up to 1.7 mm.

The jig operates with 300 pulsations per minute, considering these factors the interstitial relation is determined: 1.7 / 0.4 = 4.25 where d = D / 4.25.

For the calculus of the speed of the particles, the following formula is given:

• V = the velocity in mm.
• D = the diameter in half a particle and
• d = the density.
• If 60 V = 2 cn than for one particle of 4mm. in diameter:
• V = 26.32 (2.64 -1.0)
• = 67.41 mm per minute
• = 4044.72 mm per minute
• If c = 20 mm.
• We have n = 4044.72/2 x 20 -101.1 RPM
• c = 4044.72/2 x 190 = 10. 64 mm.

the maximum speed of an eccentric with a minimum amount of time of 0.2 seconds for each cycle gives us: 60/0.2 = 300 RPM.

Scheduling capacities

• Primary jig of 42 inches (3.5 feet) with variable particle sizing of -3 mm. + 120 mesh.
• Treats: 17 tones per hour
• Secondary jig of 42 inches, idem previous particle sizing
• Treats: 25 tones per hour
• Tertiary jig of 42 inches, idem previous particle sizing
• Treats: 30 tones per hour